What is the answer to solvefor x,log_{2}(2x+1)=3 ?

The answer to solvefor x,log_{2}(2x+1)=3 is x= 7/2

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solvefor x,log_{2}(2x+1)=3

solve for

x, lo g_{2} (2 x + 1) = 3

x = \frac{7}{2}

Decimal Notation

x = 3.5

Solution steps

lo g_{2} (2 x + 1) = 3

Apply log rules

2 x + 1 = 8

Solve

2 x + 1 = 8 : x = \frac{7}{2}

x = \frac{7}{2}

4631 = ln (\frac{A}{500})

ln (A) = - 2 k t + c, A

ln (10 x^{13}) = 65

lo g_{4} (3 x) - 1 = lo g_{4} (- 2 x + 9)

ln (7 x + e) = - 6

What is the answer to solvefor x,log_{2}(2x+1)=3 ?
The answer to solvefor x,log_{2}(2x+1)=3 is x= 7/2