What is the answer to 4.48=-log_{10}(x) ?

The answer to 4.48=-log_{10}(x) is x= 1/(10^{4.48)}

Solve for x: 4.48=-log_{10}(x)

The solution is x= 1/(10^{4.48)}

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4.48 = - lo g_{10} (x)

x = \frac{1}{1 0 ^{4.48}}

Decimal Notation

x = 0.00003 \dots

Solution steps

4.48 = - lo g_{10} (x)

Move

lo g_{10} (x)

to the left side

4.48 + lo g_{10} (x) = 0

Move

4.48

to the right side

lo g_{10} (x) = - 4.48

Apply log rules

x = \frac{1}{1 0 ^{4.48}}

Verify Solutions:

x = \frac{1}{1 0 ^{4.48}}

True

The solution is

x = \frac{1}{1 0 ^{4.48}}

lo g_{2} (2 x - 1) + 4 = lo g_{2} (x)

lo g_{10} (3 x + 3) = 3

5 ln (2 x + 5) - 14 = 1616

x, lo g_{x} (36) = 1.842

lo g_{10} (x) = 4.4 + 1.5 (2.8)

What is the answer to 4.48=-log_{10}(x) ?
The answer to 4.48=-log_{10}(x) is x= 1/(10^{4.48)}
Solve for x: 4.48=-log_{10}(x)
The solution is x= 1/(10^{4.48)}