What is the answer to log_{2}(x)-log_{2}(16)=3 ?

The answer to log_{2}(x)-log_{2}(16)=3 is x=128

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log_{2}(x)-log_{2}(16)=3

lo g_{2} (x) - lo g_{2} (16) = 3

x = 128

Solution steps

lo g_{2} (x) - lo g_{2} (16) = 3

Move

lo g_{2} (16)

to the right side

lo g_{2} (x) = 3 + lo g_{2} (16)

Apply log rules

x = 128

Verify Solutions:

x = 128

True

The solution is

x = 128

n = ln^{2} (x)

lo g_{8} (X) = \frac{1}{3}

5 ln (6 x - 2) + 13 = 23

lo g_{x} (25) = lo g_{5} (125) - 1

127 = lo g_{2} (x)

What is the answer to log_{2}(x)-log_{2}(16)=3 ?
The answer to log_{2}(x)-log_{2}(16)=3 is x=128
Solve for x: log_{2}(x)-log_{2}(16)=3
The solution is x=128