What is the answer to |2x+1|=10 ?

The answer to |2x+1|=10 is x=-11/2 \lor x= 9/2

Solve for x: |2x+1|=10

The solution is x=-11/2 \lor x= 9/2

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∣ 2 x + 1 ∣ = 10

x = - \frac{11}{2} or x = \frac{9}{2}

Decimal Notation

x = - 5.5, x = 4.5

Solution steps

∣ 2 x + 1 ∣ = 10

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

2 x + 1 = - 10 or 2 x + 1 = 10

2 x + 1 = - 10 or 2 x + 1 = 10

x = - \frac{11}{2} or x = \frac{9}{2}

\frac{3}{4} (2^{3} + 4^{2})

\frac{1}{3} x = 12

2 x + 3 (5 x - 7) = 47

x^{2} - 14 x + 50 = 0

(2 - x)^{2} (x - \frac{9}{2}) < 0

What is the answer to |2x+1|=10 ?
The answer to |2x+1|=10 is x=-11/2 \lor x= 9/2
Solve for x: |2x+1|=10
The solution is x=-11/2 \lor x= 9/2