What is the answer to log_{7}(x)+log_{7}(x-48)=2 ?

The answer to log_{7}(x)+log_{7}(x-48)=2 is x=49

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log_{7}(x)+log_{7}(x-48)=2

lo g_{7} (x) + lo g_{7} (x - 48) = 2

x = 49

Solution steps

lo g_{7} (x) + lo g_{7} (x - 48) = 2

Apply log rules

x (x - 48) = 49

Solve

x (x - 48) = 49 : x = 49, x = - 1

x = 49, x = - 1

Verify Solutions:

x = 49

True

, x = - 1

False

The solution is

x = 49

0.88 = ln (y)

lo g_{4} (x) + 5 lo g_{2} (x) - 36 = 0

lo g_{10} (d) = 3.7 - 0.2 \cdot 20

lo g_{x} (3 x^{2} - 13 x + 15) = 2

- 2 ln (5 x) = ln (9) - ln (5)

What is the answer to log_{7}(x)+log_{7}(x-48)=2 ?
The answer to log_{7}(x)+log_{7}(x-48)=2 is x=49
Solve for x: log_{7}(x)+log_{7}(x-48)=2
The solution is x=49