What is the answer to log_{10}(3x^2-2x)=0 ?

The answer to log_{10}(3x^2-2x)=0 is x=1,x=-1/3

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log_{10}(3x^2-2x)=0

lo g_{10} (3 x^{2} - 2 x) = 0

x = 1, x = - \frac{1}{3}

Decimal Notation

x = 1, x = - 0.33333 \dots

Solution steps

lo g_{10} (3 x^{2} - 2 x) = 0

Apply log rules

3 x^{2} - 2 x = 1

Solve

3 x^{2} - 2 x = 1 : x = 1, x = - \frac{1}{3}

x = 1, x = - \frac{1}{3}

lo g_{9} (x^{2} - x + 3) = 0.5

- 1 + ln (x + 3) = 0

2 lo g_{4 x} (x) = 3

lo g_{10} (x) = 6.15

lo g_{7} (x - 8) = 2

What is the answer to log_{10}(3x^2-2x)=0 ?
The answer to log_{10}(3x^2-2x)=0 is x=1,x=-1/3
Solve for x: log_{10}(3x^2-2x)=0
The solution is x=1,x=-1/3