What is the answer to log_{9}(x^2-x+3)=0.5 ?

The answer to log_{9}(x^2-x+3)=0.5 is x=1,x=0

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log_{9}(x^2-x+3)=0.5

lo g_{9} (x^{2} - x + 3) = 0.5

x = 1, x = 0

Solution steps

lo g_{9} (x^{2} - x + 3) = 0.5

Apply log rules

x^{2} - x + 3 = 3

Solve

x^{2} - x + 3 = 3 : x = 1, x = 0

x = 1, x = 0

- 1 + ln (x + 3) = 0

2 lo g_{4 x} (x) = 3

lo g_{10} (x) = 6.15

lo g_{7} (x - 8) = 2

- lo g_{2} (x + 7) = 2 - lo g_{2} (x + 4)

What is the answer to log_{9}(x^2-x+3)=0.5 ?
The answer to log_{9}(x^2-x+3)=0.5 is x=1,x=0
Solve for x: log_{9}(x^2-x+3)=0.5
The solution is x=1,x=0