What is the answer to -log_{2}(x+7)=2-log_{2}(x+4) ?

The answer to -log_{2}(x+7)=2-log_{2}(x+4) is No Solution for x\in\mathbb{R}

Solve for x: -log_{2}(x+7)=2-log_{2}(x+4)

The solution is No Solution for x\in\mathbb{R}

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- lo g_{2} (x + 7) = 2 - lo g_{2} (x + 4)

No Solution for x \in R

Solution steps

- lo g_{2} (x + 7) = 2 - lo g_{2} (x + 4)

Add

lo g_{2} (x + 7)

to both sides

- lo g_{2} (x + 7) + lo g_{2} (x + 7) = 2 - lo g_{2} (x + 4) + lo g_{2} (x + 7)

Simplify

0 = 2 - lo g_{2} (x + 4) + lo g_{2} (x + 7)

Add

lo g_{2} (x + 4)

to both sides

0 + lo g_{2} (x + 4) = 2 - lo g_{2} (x + 4) + lo g_{2} (x + 7) + lo g_{2} (x + 4)

Simplify

lo g_{2} (x + 4) = lo g_{2} (x + 7) + 2

Apply log rules

x + 4 = (x + 7) \cdot 4

Solve

x + 4 = (x + 7) \cdot 4 : x = - 8

x = - 8

Verify Solutions:

x = - 8

False

The solution is

No Solution for x \in R

lo g_{5} (5 x + 3) - lo g_{5} (3 - x) = 1

lo g_{x} (3) = 3 lo g_{3} (9) x

lo g_{10} (3^{3 x + 1}) = 9^{x}

lo g_{3} (4 x + 6) = 4

3 lo g_{10} (10 x) - 2 = 10

What is the answer to -log_{2}(x+7)=2-log_{2}(x+4) ?
The answer to -log_{2}(x+7)=2-log_{2}(x+4) is No Solution for x\in\mathbb{R}
Solve for x: -log_{2}(x+7)=2-log_{2}(x+4)
The solution is No Solution for x\in\mathbb{R}