What is the answer to log_{10}(3^{3x+1})=9^x ?

The answer to log_{10}(3^{3x+1})=9^x is No Solution for x\in\mathbb{R}

Solve for x: log_{10}(3^{3x+1})=9^x

The solution is No Solution for x\in\mathbb{R}

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lo g_{10} (3^{3 x + 1}) = 9^{x}

No Solution for x \in R

Solution steps

lo g_{10} (3^{3 x + 1}) = 9^{x}

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

1 0^{l o g_{10} (3^{3 x + 1})} = 1 0^{9^{x}}

Simplify

1 0^{l o g_{10} (3^{3 x + 1})} : 3^{3 x + 1}

3^{3 x + 1} = 1 0^{9^{x}}

Solve

3^{3 x + 1} = 1 0^{9^{x}} :

No Solution for

x \in R

No Solution for x \in R

lo g_{3} (4 x + 6) = 4

3 lo g_{10} (10 x) - 2 = 10

ln (x - 3) = ln (7 x - 23) - ln (x + 1)

- x + 4 = ln (x)

lo g_{2} (x) + lo g_{2} (x + 2) = 2

What is the answer to log_{10}(3^{3x+1})=9^x ?
The answer to log_{10}(3^{3x+1})=9^x is No Solution for x\in\mathbb{R}
Solve for x: log_{10}(3^{3x+1})=9^x
The solution is No Solution for x\in\mathbb{R}