What is the answer to -x+4=ln(x) ?

The answer to -x+4=ln(x) is x=\W_{0}(e^4)

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-x+4=ln(x)

- x + 4 = ln (x)

x = W_{0} (e^{4})

Decimal Notation

x = 2.92627 \dots

Solution steps

- x + 4 = ln (x)

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{- x + 4} = e^{l n (x)}

Simplify

e^{l n (x)} : x

e^{- x + 4} = x

Solve

e^{- x + 4} = x : x = W_{0} (e^{4})

x = W_{0} (e^{4})

Verify Solutions:

x = W_{0} (e^{4})

True

The solution is

x = W_{0} (e^{4})

lo g_{2} (x) + lo g_{2} (x + 2) = 2

ln (10 x + 5) - 3 = ln (x - 5)

7 lo g_{2} (x) = - \frac{7}{3}

x, 2 - 2.12 = lo g_{10} (x)

lo g_{7} (x + 4) = 0