What is the answer to solvefor x,ln(x)=-ln(y)-y+c ?

The answer to solvefor x,ln(x)=-ln(y)-y+c is x=(e^{-y+c})/y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,ln(x)=-ln(y)-y+c

solve for

x, ln (x) = - ln (y) - y + c

x = \frac{e ^{- y + c}}{y}

Solution steps

ln (x) = - ln (y) - y + c

Apply log rules

x = \frac{e ^{- y + c}}{y}

x, 1 + lo g_{2} (- 5 x) = 4

x, lo g_{2} (6 x + 4) = 1

lo g_{y} (25) = 2

ln (x) + ln (7 x) = 4

- ln (3 - x) = ln (2 + x)

What is the answer to solvefor x,ln(x)=-ln(y)-y+c ?
The answer to solvefor x,ln(x)=-ln(y)-y+c is x=(e^{-y+c})/y