What is the answer to ln(3x^2+2x)=0 ?

The answer to ln(3x^2+2x)=0 is x= 1/3 ,x=-1

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ln(3x^2+2x)=0

ln (3 x^{2} + 2 x) = 0

x = \frac{1}{3}, x = - 1

Decimal Notation

x = 0.33333 \dots, x = - 1

Solution steps

ln (3 x^{2} + 2 x) = 0

Apply log rules

3 x^{2} + 2 x = 1

Solve

3 x^{2} + 2 x = 1 : x = \frac{1}{3}, x = - 1

x = \frac{1}{3}, x = - 1

lo g_{3} (7 x - 1) = 3

lo g_{5} (9 x) + 2 lo g_{5} (3) = 2

12 lo g_{x} (5) + lo g_{5} (x) - 7 = 0

4 ln (x + 1) = 12

x, g = lo g_{4} (x - 3)

What is the answer to ln(3x^2+2x)=0 ?
The answer to ln(3x^2+2x)=0 is x= 1/3 ,x=-1
Solve for x: ln(3x^2+2x)=0
The solution is x= 1/3 ,x=-1