What is the answer to solvefor x,g=log_{4}(x-3) ?

The answer to solvefor x,g=log_{4}(x-3) is x=4^g+3

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solvefor x,g=log_{4}(x-3)

solve for

x, g = lo g_{4} (x - 3)

x = 4^{g} + 3

Solution steps

g = lo g_{4} (x - 3)

Apply log rules

4^{g} = x - 3

Solve

4^{g} = x - 3 : x = 4^{g} + 3

x = 4^{g} + 3

lo g_{10} (2 x + 3) = lo g_{10} (x + 5)

ln (x^{2} - x + 17) = \frac{3}{4}

3 lo g_{4} (x + 4) - lo g_{4} (x + 4) = 2

- ln (x^{5}) = - 5 ln (x)

ln (3 x + 3) = ln (5 x - 9)

What is the answer to solvefor x,g=log_{4}(x-3) ?
The answer to solvefor x,g=log_{4}(x-3) is x=4^g+3