What is the answer to 3.982=-log_{10}(b) ?

The answer to 3.982=-log_{10}(b) is b= 1/(10^{3.982)}

Solve for b: 3.982=-log_{10}(b)

The solution is b= 1/(10^{3.982)}

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3.982 = - lo g_{10} (b)

b = \frac{1}{1 0 ^{3.982}}

Decimal Notation

b = 0.00010 \dots

Solution steps

3.982 = - lo g_{10} (b)

Move

lo g_{10} (b)

to the left side

3.982 + lo g_{10} (b) = 0

Move

3.982

to the right side

lo g_{10} (b) = - 3.982

Apply log rules

b = \frac{1}{1 0 ^{3.982}}

Verify Solutions:

b = \frac{1}{1 0 ^{3.982}}

True

The solution is

b = \frac{1}{1 0 ^{3.982}}

x^{2} ln (x + y) = 0

lo g_{10} (5 x) + lo g_{10} (3 x) = 1

lo g_{4} (x + 8) + lo g_{4} (x + 5) = 1

lo g_{b} (5) = \frac{1}{4}

6 - 4.79 = 5 lo g_{10} (d - 5)

What is the answer to 3.982=-log_{10}(b) ?
The answer to 3.982=-log_{10}(b) is b= 1/(10^{3.982)}
Solve for b: 3.982=-log_{10}(b)
The solution is b= 1/(10^{3.982)}