What is the answer to log_{b}(x+2)=log_{b}(x)+2 ?

The answer to log_{b}(x+2)=log_{b}(x)+2 is x=-2/(1-b^2) {b>1}

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log_{b}(x+2)=log_{b}(x)+2

lo g_{b} (x + 2) = lo g_{b} (x) + 2

x = - \frac{2}{1 - b ^{2}} {b > 1}

Solution steps

lo g_{b} (x + 2) = lo g_{b} (x) + 2

Apply log rules

x + 2 = x b^{2}

Solve

x + 2 = x b^{2} : x = - \frac{2}{1 - b ^{2}}

x = - \frac{2}{1 - b ^{2}}

Verify Solutions:

x = - \frac{2}{1 - b ^{2}} {b > 1}

The solution is

x = - \frac{2}{1 - b ^{2}} {b > 1}

ln (5 x + 4) = 7.9

lo g_{6} (2 x - 7) = 4

\frac{k ( x )}{x} + k (x) ln (x) = 0

5 lo g_{10} (x) = 12

e^{3 l n (x)} = x

What is the answer to log_{b}(x+2)=log_{b}(x)+2 ?
The answer to log_{b}(x+2)=log_{b}(x)+2 is x=-2/(1-b^2) {b>1}