What are the solutions to the equation y^2-9y+4=0 ?

The solutions to the equation y^2-9y+4=0 are y=(9+sqrt(65))/2 ,y=(9-sqrt(65))/2

Find the zeros of y^2-9y+4=0

The zeros of y^2-9y+4=0 are y=(9+sqrt(65))/2 ,y=(9-sqrt(65))/2

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y^{2} - 9 y + 4 = 0

y = \frac{9 + 65}{2}, y = \frac{9 - 65}{2}

Decimal Notation

y = 8.53112 \dots, y = 0.46887 \dots

Solution steps

y^{2} - 9 y + 4 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 4 = 65

y_{1, 2} = \frac{- ( - 9 ) \pm 65}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 9 ) + 65}{2 \cdot 1}, y_{2} = \frac{- ( - 9 ) - 65}{2 \cdot 1}

y = \frac{- ( - 9 ) + 65}{2 \cdot 1} : \frac{9 + 65}{2}

y = \frac{- ( - 9 ) - 65}{2 \cdot 1} : \frac{9 - 65}{2}

The solutions to the quadratic equation are:

y = \frac{9 + 65}{2}, y = \frac{9 - 65}{2}

\frac{y}{4} \geq 2.4

8 x^{2} + 16 x = 42

- 2 = \frac{m}{16}

\frac{x + 1}{3} - \frac{2 x + 4}{4} = x + 4

3 ∣ m + 7 ∣ + 9 < 30

What are the solutions to the equation y^2-9y+4=0 ?
The solutions to the equation y^2-9y+4=0 are y=(9+sqrt(65))/2 ,y=(9-sqrt(65))/2
Find the zeros of y^2-9y+4=0
The zeros of y^2-9y+4=0 are y=(9+sqrt(65))/2 ,y=(9-sqrt(65))/2