What are the solutions to the equation 8x^2+16x=42 ?

The solutions to the equation 8x^2+16x=42 are x= 3/2 ,x=-7/2

Find the zeros of 8x^2+16x=42

The zeros of 8x^2+16x=42 are x= 3/2 ,x=-7/2

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8 x^{2} + 16 x = 42

x = \frac{3}{2}, x = - \frac{7}{2}

Solution steps

8 x^{2} + 16 x = 42

Move

42

to the left side

8 x^{2} + 16 x - 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 8 ( - 42 )}{2 \cdot 8}

1 6^{2} - 4 \cdot 8 (- 42) = 40

x_{1, 2} = \frac{- 16 \pm 40}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 16 + 40}{2 \cdot 8}, x_{2} = \frac{- 16 - 40}{2 \cdot 8}

x = \frac{- 16 + 40}{2 \cdot 8} : \frac{3}{2}

x = \frac{- 16 - 40}{2 \cdot 8} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{7}{2}

- 2 = \frac{m}{16}

\frac{x + 1}{3} - \frac{2 x + 4}{4} = x + 4

3 ∣ m + 7 ∣ + 9 < 30

\frac{3}{- 8}

- 8 x^{2} + 7 x + 6 = 2

What are the solutions to the equation 8x^2+16x=42 ?
The solutions to the equation 8x^2+16x=42 are x= 3/2 ,x=-7/2
Find the zeros of 8x^2+16x=42
The zeros of 8x^2+16x=42 are x= 3/2 ,x=-7/2