What is the answer to log_{2}(x)+log_{2}(4x)-4=0 ?

The answer to log_{2}(x)+log_{2}(4x)-4=0 is x=2

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log_{2}(x)+log_{2}(4x)-4=0

lo g_{2} (x) + lo g_{2} (4 x) - 4 = 0

x = 2

Solution steps

lo g_{2} (x) + lo g_{2} (4 x) - 4 = 0

Apply log rules

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

2 lo g_{3} (x) - lo g_{3} (x + 6) = 1

2 lo g_{12} (x - 3) + lo g_{12} (4) = 2

lo g_{10} (x) = 3.931

4 ln (7 x + 2) - 7 = - 15

4.35 = 7 - lo g_{10} (x)

What is the answer to log_{2}(x)+log_{2}(4x)-4=0 ?
The answer to log_{2}(x)+log_{2}(4x)-4=0 is x=2
Solve for x: log_{2}(x)+log_{2}(4x)-4=0
The solution is x=2