What is the answer to 2log_{a}(x)=log_{a}(16)+4 ?

The answer to 2log_{a}(x)=log_{a}(16)+4 is x=4a^2

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2log_{a}(x)=log_{a}(16)+4

2 lo g_{a} (x) = lo g_{a} (16) + 4

x = 4 a^{2}

Solution steps

2 lo g_{a} (x) = lo g_{a} (16) + 4

Divide both sides by

2

lo g_{a} (x) = \frac{lo g _{a} ( 16 ) + 4}{2}

Apply log rules

x = 4 a^{2}

Verify Solutions:

x = 4 a^{2}

True

The solution is

x = 4 a^{2}

ln (x + \frac{1}{2}) = ln (2 x + 1)

- 35 = 10 lo g_{10} (\frac{x}{1})

lo g_{10} (lo g_{10} (x)) = 4

lo g_{x} (3) = lo g_{3} (9 x)^{3}

\frac{1}{e ^{0.243}} = ln (x)

What is the answer to 2log_{a}(x)=log_{a}(16)+4 ?
The answer to 2log_{a}(x)=log_{a}(16)+4 is x=4a^2