What is the answer to log_{3}(-2x+6)=log_{3}(x-2) ?

The answer to log_{3}(-2x+6)=log_{3}(x-2) is x= 8/3

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log_{3}(-2x+6)=log_{3}(x-2)

lo g_{3} (- 2 x + 6) = lo g_{3} (x - 2)

x = \frac{8}{3}

Decimal Notation

x = 2.66666 \dots

Solution steps

lo g_{3} (- 2 x + 6) = lo g_{3} (x - 2)

Apply log rules

- 2 x + 6 = x - 2

Solve

- 2 x + 6 = x - 2 : x = \frac{8}{3}

x = \frac{8}{3}

Verify Solutions:

x = \frac{8}{3}

True

The solution is

x = \frac{8}{3}

6 lo g_{8} (3 x + 1) = lo g_{8} (64)

x = lo g_{3} (x)

(x) 6 - 5 ln (x) = 2

ln (\frac{1}{x}) = 1.147629

lo g_{3} (x) - lo g_{3} (x + 5) = 1

What is the answer to log_{3}(-2x+6)=log_{3}(x-2) ?
The answer to log_{3}(-2x+6)=log_{3}(x-2) is x= 8/3
Solve for x: log_{3}(-2x+6)=log_{3}(x-2)
The solution is x= 8/3