What is the answer to log_{8}(3x-1)=log_{8}(x+4) ?

The answer to log_{8}(3x-1)=log_{8}(x+4) is x= 5/2

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log_{8}(3x-1)=log_{8}(x+4)

lo g_{8} (3 x - 1) = lo g_{8} (x + 4)

x = \frac{5}{2}

Decimal Notation

x = 2.5

Solution steps

lo g_{8} (3 x - 1) = lo g_{8} (x + 4)

Apply log rules

3 x - 1 = x + 4

Solve

3 x - 1 = x + 4 : x = \frac{5}{2}

x = \frac{5}{2}

Verify Solutions:

x = \frac{5}{2}

True

The solution is

x = \frac{5}{2}

20 lo g_{10} (k) = 6.02

lo g_{b} (32) = \frac{5}{6}

lo g_{2} (x) + lo g_{2} (2 x - 3) = 1

2 lo g_{3} (x) - 3 = 0

ln (x - 5) = - 1

What is the answer to log_{8}(3x-1)=log_{8}(x+4) ?
The answer to log_{8}(3x-1)=log_{8}(x+4) is x= 5/2
Solve for x: log_{8}(3x-1)=log_{8}(x+4)
The solution is x= 5/2