What is the answer to 4ln(x)=ln(4x) ?

The answer to 4ln(x)=ln(4x) is x=e^{(2ln(2))/3}

Solve for x: 4ln(x)=ln(4x)

The solution is x=e^{(2ln(2))/3}

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4 ln (x) = ln (4 x)

x = e^{\frac{2 l n ( 2 )}{3}}

Decimal Notation

x = 1.58740 \dots

Solution steps

4 ln (x) = ln (4 x)

Apply log rules

x = e^{\frac{2 l n ( 2 )}{3}}

Verify Solutions:

x = e^{\frac{2 l n ( 2 )}{3}}

True

The solution is

x = e^{\frac{2 l n ( 2 )}{3}}

lo g_{3} (x + 9) + lo g_{3} (x + 1) = 1

x \frac{1}{240} = ln (x)

ln^{(2)} (x^{(3)}) = e

e^{- 2 l n (x)} = - 2 x

lo g_{6} (7 x) = 4

What is the answer to 4ln(x)=ln(4x) ?
The answer to 4ln(x)=ln(4x) is x=e^{(2ln(2))/3}
Solve for x: 4ln(x)=ln(4x)
The solution is x=e^{(2ln(2))/3}