What is the answer to log_{3}((2x-3)*(x+3))=4 ?

The answer to log_{3}((2x-3)*(x+3))=4 is x=6,x=-15/2

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log_{3}((2x-3)*(x+3))=4

lo g_{3} ((2 x - 3) \cdot (x + 3)) = 4

x = 6, x = - \frac{15}{2}

Decimal Notation

x = 6, x = - 7.5

Solution steps

lo g_{3} ((2 x - 3) (x + 3)) = 4

Apply log rules

(2 x - 3) (x + 3) = 81

Solve

(2 x - 3) (x + 3) = 81 : x = 6, x = - \frac{15}{2}

x = 6, x = - \frac{15}{2}

lo g_{5} (8 y - 6) + lo g_{5} (y - 5) = 4

2.1 = - lo g_{10} (h)

- 2 ln (a) = ln (9)

ln^{2} (x) = ln^{3} (x)

y, 3 ln (x + 4) = ln (y)

What is the answer to log_{3}((2x-3)*(x+3))=4 ?
The answer to log_{3}((2x-3)*(x+3))=4 is x=6,x=-15/2
Solve for x: log_{3}((2x-3)*(x+3))=4
The solution is x=6,x=-15/2