What is the answer to 2.9=-log_{10}(H) ?

The answer to 2.9=-log_{10}(H) is H= 1/(10^{2.9)}

Solve for H: 2.9=-log_{10}(H)

The solution is H= 1/(10^{2.9)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2.9 = - lo g_{10} (H)

H = \frac{1}{1 0 ^{2.9}}

Decimal

H = 0.00125 \dots

Solution steps

2.9 = - lo g_{10} (H)

Move

lo g_{10} (H)

to the left side

2.9 + lo g_{10} (H) = 0

Move

2.9

to the right side

lo g_{10} (H) = - 2.9

Apply log rules

H = \frac{1}{1 0 ^{2.9}}

Verify Solutions:

H = \frac{1}{1 0 ^{2.9}}

True

The solution is

H = \frac{1}{1 0 ^{2.9}}

lo g_{3} (x - 11) = 0

lo g_{x} (0.001) = 2

3.81 = - lo g_{10} (ka)

lo g_{10} (x) = 2.644

lo g_{10} (y) (\frac{1}{256}) = - 4

What is the answer to 2.9=-log_{10}(H) ?
The answer to 2.9=-log_{10}(H) is H= 1/(10^{2.9)}
Solve for H: 2.9=-log_{10}(H)
The solution is H= 1/(10^{2.9)}