What is the answer to log_{5}((x+1)^4)=12 ?

The answer to log_{5}((x+1)^4)=12 is x=124,x=-126

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log_{5}((x+1)^4)=12

lo g_{5} ((x + 1)^{4}) = 12

x = 124, x = - 126

Solution steps

lo g_{5} ((x + 1)^{4}) = 12

Apply exponent rule:

a^{2 \cdot n} = (a^{2})^{n}

(x + 1)^{4} = ((x + 1)^{2})^{2}

lo g_{5} (((x + 1)^{2})^{2}) = 12

Apply log rules

(x + 1)^{2} = 15625

Solve

(x + 1)^{2} = 15625 : x = 124, x = - 126

x = 124, x = - 126

Verify Solutions:

x = 124

True

, x = - 126

True

The solutions are

x = 124, x = - 126

lo g_{2} (2 x - 5) + lo g_{2} (x + 1) = 1

- lo g_{10} (x) = 5.59

3 ln (4 x) = - 3

lo g_{5} (x) + lo g_{3} (x) = 1

1 = - ln (1 - x) - ln (x)

What is the answer to log_{5}((x+1)^4)=12 ?
The answer to log_{5}((x+1)^4)=12 is x=124,x=-126
Solve for x: log_{5}((x+1)^4)=12
The solution is x=124,x=-126