What is the answer to ln(x)=-5.19335 ?

The answer to ln(x)=-5.19335 is x= 1/(e^{5.19335)}

Solve for x: ln(x)=-5.19335

The solution is x= 1/(e^{5.19335)}

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ln (x) = - 5.19335

x = \frac{1}{e ^{5.19335}}

Decimal Notation

x = 0.00555 \dots

Solution steps

ln (x) = - 5.19335

Apply log rules

x = \frac{1}{e ^{5.19335}}

5 ln (x) - x = 0

- 14 = lo g_{7} (\frac{2 b}{14 b})

lo g_{2} (2) = - lo g_{2} (x)

ln (2 x - 1) = 1

ln (2 x - 1) = 5

What is the answer to ln(x)=-5.19335 ?
The answer to ln(x)=-5.19335 is x= 1/(e^{5.19335)}
Solve for x: ln(x)=-5.19335
The solution is x= 1/(e^{5.19335)}