What is the answer to ln(x)+ln(x+12)=4 ?

The answer to ln(x)+ln(x+12)=4 is x=(-12+sqrt(144+4e^4))/2

Solve for x: ln(x)+ln(x+12)=4

The solution is x=(-12+sqrt(144+4e^4))/2

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ln (x) + ln (x + 12) = 4

x = \frac{- 12 + 144 + 4 e ^{4}}{2}

Decimal Notation

x = 3.51830 \dots

Solution steps

ln (x) + ln (x + 12) = 4

Apply log rules

x (x + 12) = e^{4}

Solve

x (x + 12) = e^{4} : x = \frac{- 12 + 144 + 4 e ^{4}}{2}, x = \frac{- 12 - 144 + 4 e ^{4}}{2}

x = \frac{- 12 + 144 + 4 e ^{4}}{2}, x = \frac{- 12 - 144 + 4 e ^{4}}{2}

Verify Solutions:

x = \frac{- 12 + 144 + 4 e ^{4}}{2}

True

, x = \frac{- 12 - 144 + 4 e ^{4}}{2}

False

The solution is

x = \frac{- 12 + 144 + 4 e ^{4}}{2}

ln (x) + ln (x + 12) = 3

ln (1 - (1)^{2} + 2 c) = 0

ln (x + 1) = 10

5 ln (x) + 3 ln (\frac{1}{x}) = 10

x^{l n (17)} + 1 7^{l n (x)} = 34

What is the answer to ln(x)+ln(x+12)=4 ?
The answer to ln(x)+ln(x+12)=4 is x=(-12+sqrt(144+4e^4))/2
Solve for x: ln(x)+ln(x+12)=4
The solution is x=(-12+sqrt(144+4e^4))/2