What is the answer to ln(1-sqrt((1)^2+2c))=0 ?

The answer to ln(1-sqrt((1)^2+2c))=0 is c=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ln(1-sqrt((1)^2+2c))=0

ln (1 - (1)^{2} + 2 c) = 0

c = - \frac{1}{2}

Decimal Notation

c = - 0.5

Solution steps

ln (1 - (1)^{2} + 2 c) = 0

Apply log rules

1 - 1 + 2 c = 1

Solve

1 - 1 + 2 c = 1 : c = - \frac{1}{2}

c = - \frac{1}{2}

ln (x + 1) = 10

5 ln (x) + 3 ln (\frac{1}{x}) = 10

x^{l n (17)} + 1 7^{l n (x)} = 34

ln (x^{2} - 1) = ln (x + 1)

65 = 9 \cdot ln (x) + 44

What is the answer to ln(1-sqrt((1)^2+2c))=0 ?
The answer to ln(1-sqrt((1)^2+2c))=0 is c=-1/2
Solve for c: ln(1-sqrt((1)^2+2c))=0
The solution is c=-1/2