What is the answer to ln(7)=ln(10)+ln(x^2+5) ?

The answer to ln(7)=ln(10)+ln(x^2+5) is No Solution for x\in\mathbb{R}

Solve for x: ln(7)=ln(10)+ln(x^2+5)

The solution is No Solution for x\in\mathbb{R}

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ln (7) = ln (10) + ln (x^{2} + 5)

No Solution for x \in R

Solution steps

ln (7) = ln (10) + ln (x^{2} + 5)

Switch sides

ln (10) + ln (x^{2} + 5) = ln (7)

Move

ln (10)

to the right side

ln (x^{2} + 5) = ln (7) - ln (10)

Apply log rules

x^{2} + 5 = \frac{7}{10}

Solve

x^{2} + 5 = \frac{7}{10} :

No Solution for

x \in R

No Solution for x \in R

2 + ln (x - 1) = 4

lo g_{2} (2 x - 6) = 3 + lo g_{2} (x + 3)

ln (x) = 7.990346728

lo g_{7} (x) = 24

lo g_{2} (4 x - 3) = lo g_{2} (2 x + 1)

What is the answer to ln(7)=ln(10)+ln(x^2+5) ?
The answer to ln(7)=ln(10)+ln(x^2+5) is No Solution for x\in\mathbb{R}
Solve for x: ln(7)=ln(10)+ln(x^2+5)
The solution is No Solution for x\in\mathbb{R}