What is the answer to ln(x+1)=6-7x ?

The answer to ln(x+1)=6-7x is x=(\W_{0}(7e^{13})-7)/7

Solve for x: ln(x+1)=6-7x

The solution is x=(\W_{0}(7e^{13})-7)/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ln (x + 1) = 6 - 7 x

x = \frac{W _{0} ( 7 e ^{13} ) - 7}{7}

Decimal Notation

x = 0.77515 \dots

Solution steps

ln (x + 1) = 6 - 7 x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x + 1)} = e^{6 - 7 x}

Simplify

e^{l n (x + 1)} : x + 1

x + 1 = e^{6 - 7 x}

Solve

x + 1 = e^{6 - 7 x} : x = \frac{W _{0} ( 7 e ^{13} ) - 7}{7}

x = \frac{W _{0} ( 7 e ^{13} ) - 7}{7}

Verify Solutions:

x = \frac{W _{0} ( 7 e ^{13} ) - 7}{7}

True

The solution is

x = \frac{W _{0} ( 7 e ^{13} ) - 7}{7}

lo g_{7} (2 x + 1) + lo g_{7} (x - 1) = 1

ln (e - 8 x + 1 - 1) = 20, x

x, 20 = - 20 lo g_{10} (x)

2 ln (t + 2) = 0

lo g_{10} (a x) = 6

What is the answer to ln(x+1)=6-7x ?
The answer to ln(x+1)=6-7x is x=(\W_{0}(7e^{13})-7)/7
Solve for x: ln(x+1)=6-7x
The solution is x=(\W_{0}(7e^{13})-7)/7