What is the answer to ln(n^2+12)=ln(-9n-2) ?

The answer to ln(n^2+12)=ln(-9n-2) is n=-2,n=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ln(n^2+12)=ln(-9n-2)

ln (n^{2} + 12) = ln (- 9 n - 2)

n = - 2, n = - 7

Solution steps

ln (n^{2} + 12) = ln (- 9 n - 2)

Apply log rules

n^{2} + 12 = - 9 n - 2

Solve

n^{2} + 12 = - 9 n - 2 : n = - 2, n = - 7

n = - 2, n = - 7

Verify Solutions:

n = - 2

True

, n = - 7

True

The solutions are

n = - 2, n = - 7

lo g_{2} (x + 1) - 2 lo g_{2} (3) = 3

7.5 = 10.5 + lo g_{10} (x)

lo g_{3} ((r + 10)^{2}) = 4

lo g_{2} (x) + 3 = lo g_{2} (5 x)

- lo g_{10} (x) = 2.6

What is the answer to ln(n^2+12)=ln(-9n-2) ?
The answer to ln(n^2+12)=ln(-9n-2) is n=-2,n=-7
Solve for n: ln(n^2+12)=ln(-9n-2)
The solution is n=-2,n=-7