What is the answer to log_{3}((r+10)^2)=4 ?

The answer to log_{3}((r+10)^2)=4 is r=-1,r=-19

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log_{3}((r+10)^2)=4

lo g_{3} ((r + 10)^{2}) = 4

r = - 1, r = - 19

Solution steps

lo g_{3} ((r + 10)^{2}) = 4

Apply log rules

(r + 10)^{2} = 81

Solve

(r + 10)^{2} = 81 : r = - 1, r = - 19

r = - 1, r = - 19

lo g_{2} (x) + 3 = lo g_{2} (5 x)

- lo g_{10} (x) = 2.6

lo g_{x} (81) = lo g_{2} (16)

5.2 lo g_{4} (2 x) = 16

ln (e x - 10) = 2

What is the answer to log_{3}((r+10)^2)=4 ?
The answer to log_{3}((r+10)^2)=4 is r=-1,r=-19
Solve for r: log_{3}((r+10)^2)=4
The solution is r=-1,r=-19