What is the answer to solvefor x,(fx)=2x+ln(x) ?

The answer to solvefor x,(fx)=2x+ln(x) is x=(\W(-f+2))/(-f+2)

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solvefor x,(fx)=2x+ln(x)

solve for

x, (f x) = 2 x + ln (x)

x = \frac{W ( - f + 2 )}{- f + 2}

Solution steps

(f x) = 2 x + ln (x)

Switch sides

2 x + ln (x) = f x

Move

2 x

to the right side

ln (x) = f x - 2 x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x)} = e^{f x - 2 x}

Simplify

e^{l n (x)} : x

x = e^{f x - 2 x}

Solve

x = e^{f x - 2 x} : x = \frac{W ( - f + 2 )}{- f + 2}

x = \frac{W ( - f + 2 )}{- f + 2}

Verify Solutions:

x = \frac{W ( - f + 2 )}{- f + 2}

True

The solution is

x = \frac{W ( - f + 2 )}{- f + 2}

3 ln (x - 1) = 0

lo g_{10} (2 x) + lo g_{10} (5) = 1

8.3 = - lo g_{10} (x)

2 lo g_{5} (x) = 1

x, y = ln (x - 6) + 4

What is the answer to solvefor x,(fx)=2x+ln(x) ?
The answer to solvefor x,(fx)=2x+ln(x) is x=(\W(-f+2))/(-f+2)