What is the answer to log_{8}(x)+log_{7}(x)=1 ?

The answer to log_{8}(x)+log_{7}(x)=1 is x=8^{(log_{8}(7))/(log_{8)(7)+1}}

Solve for x: log_{8}(x)+log_{7}(x)=1

The solution is x=8^{(log_{8}(7))/(log_{8)(7)+1}}

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lo g_{8} (x) + lo g_{7} (x) = 1

x = 8^{\frac{l o g _{8} ( 7 )}{l o g _{8} ( 7 ) + 1}}

Solution steps

lo g_{8} (x) + lo g_{7} (x) = 1

Apply log rules

x = 8^{\frac{l o g _{8} ( 7 )}{l o g _{8} ( 7 ) + 1}}

Verify Solutions:

x = 8^{\frac{l o g _{8} ( 7 )}{l o g _{8} ( 7 ) + 1}}

True

The solution is

x = 8^{\frac{l o g _{8} ( 7 )}{l o g _{8} ( 7 ) + 1}}

0 = ln (x^{2})

lo g_{3} (x) - lo g_{9} (x) = 1

3 lo g_{2} (2 x + 1) + 2 = 3

lo g_{10} (x) = \frac{19.55}{20}

3 = lo g_{2} (\frac{y}{3})

What is the answer to log_{8}(x)+log_{7}(x)=1 ?
The answer to log_{8}(x)+log_{7}(x)=1 is x=8^{(log_{8}(7))/(log_{8)(7)+1}}
Solve for x: log_{8}(x)+log_{7}(x)=1
The solution is x=8^{(log_{8}(7))/(log_{8)(7)+1}}