What is the answer to log_{2}(x)+log_{3}(5)=2 ?

The answer to log_{2}(x)+log_{3}(5)=2 is x=2^{2-log_{3}(5)}

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log_{2}(x)+log_{3}(5)=2

lo g_{2} (x) + lo g_{3} (5) = 2

x = 2^{2 - l o g_{3} (5)}

Decimal Notation

x = 1.44896 \dots

Solution steps

lo g_{2} (x) + lo g_{3} (5) = 2

Move

lo g_{3} (5)

to the right side

lo g_{2} (x) = 2 - lo g_{3} (5)

Apply log rules

x = 2^{2 - l o g_{3} (5)}

Verify Solutions:

x = 2^{2 - l o g_{3} (5)}

True

The solution is

x = 2^{2 - l o g_{3} (5)}

lo g_{2} ((x + 13) (5 x + 1)) = 8

- 10 + ln (b) = - 9

lo g_{2} (z + 4) = lo g_{2} (14 - z)

lo g_{x} (3) = 9

l (x) = lo g_{0.5} (x) - 1

What is the answer to log_{2}(x)+log_{3}(5)=2 ?
The answer to log_{2}(x)+log_{3}(5)=2 is x=2^{2-log_{3}(5)}
Solve for x: log_{2}(x)+log_{3}(5)=2
The solution is x=2^{2-log_{3}(5)}