What is the answer to log_{2}(z+4)=log_{2}(14-z) ?

The answer to log_{2}(z+4)=log_{2}(14-z) is z=5

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log_{2}(z+4)=log_{2}(14-z)

lo g_{2} (z + 4) = lo g_{2} (14 - z)

z = 5

Solution steps

lo g_{2} (z + 4) = lo g_{2} (14 - z)

Apply log rules

z + 4 = 14 - z

Solve

z + 4 = 14 - z : z = 5

z = 5

Verify Solutions:

z = 5

True

The solution is

z = 5

lo g_{x} (3) = 9

l (x) = lo g_{0.5} (x) - 1

lo g_{4} (x^{2} - x + 16) = 2

lo g_{10} (2 x) = 2 lo g_{10} (x)

lo g_{x} (3) = 5

What is the answer to log_{2}(z+4)=log_{2}(14-z) ?
The answer to log_{2}(z+4)=log_{2}(14-z) is z=5
Solve for z: log_{2}(z+4)=log_{2}(14-z)
The solution is z=5