What is the answer to log_{10}(x)-log_{10}(x+4)=1 ?

The answer to log_{10}(x)-log_{10}(x+4)=1 is No Solution for x\in\mathbb{R}

Solve for x: log_{10}(x)-log_{10}(x+4)=1

The solution is No Solution for x\in\mathbb{R}

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lo g_{10} (x) - lo g_{10} (x + 4) = 1

No Solution for x \in R

Solution steps

lo g_{10} (x) - lo g_{10} (x + 4) = 1

Add

lo g_{10} (x + 4)

to both sides

lo g_{10} (x) - lo g_{10} (x + 4) + lo g_{10} (x + 4) = 1 + lo g_{10} (x + 4)

Simplify

lo g_{10} (x) = 1 + lo g_{10} (x + 4)

Apply log rules

x = 10 (x + 4)

Solve

x = 10 (x + 4) : x = - \frac{40}{9}

x = - \frac{40}{9}

Verify Solutions:

x = - \frac{40}{9}

False

The solution is

No Solution for x \in R

ln (a) = 722

ln (T) = 1.56 + 0.82 \cdot ln (11)

2 = lo g_{10} (n)

ln (x^{2}) - 7 = 0

2 lo g_{10} (1 + x) = 2

What is the answer to log_{10}(x)-log_{10}(x+4)=1 ?
The answer to log_{10}(x)-log_{10}(x+4)=1 is No Solution for x\in\mathbb{R}
Solve for x: log_{10}(x)-log_{10}(x+4)=1
The solution is No Solution for x\in\mathbb{R}