What is the answer to log_{5}(3x^2)=log_{5}(27) ?

The answer to log_{5}(3x^2)=log_{5}(27) is x=3,x=-3

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log_{5}(3x^2)=log_{5}(27)

lo g_{5} (3 x^{2}) = lo g_{5} (27)

x = 3, x = - 3

Solution steps

lo g_{5} (3 x^{2}) = lo g_{5} (27)

Apply log rules

3 x^{2} = 27

Solve

3 x^{2} = 27 : x = 3, x = - 3

x = 3, x = - 3

Verify Solutions:

x = 3

True

, x = - 3

True

The solutions are

x = 3, x = - 3

ln (x) = e^{7}

ln (3 x) - ln (4) = 2

k, lo g_{k} (a) = b - 2

lo g_{x} (3) = 31

lo g_{x} (8) = 1 \cdot 5

What is the answer to log_{5}(3x^2)=log_{5}(27) ?
The answer to log_{5}(3x^2)=log_{5}(27) is x=3,x=-3
Solve for x: log_{5}(3x^2)=log_{5}(27)
The solution is x=3,x=-3