What is the answer to ln(3x)-ln(4)=2 ?

The answer to ln(3x)-ln(4)=2 is x=(4e^2)/3

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ln(3x)-ln(4)=2

ln (3 x) - ln (4) = 2

x = \frac{4 e ^{2}}{3}

Decimal Notation

x = 9.85207 \dots

Solution steps

ln (3 x) - ln (4) = 2

Move

ln (4)

to the right side

ln (3 x) = 2 + ln (4)

Apply log rules

3 x = 4 e^{2}

Solve

3 x = 4 e^{2} : x = \frac{4 e ^{2}}{3}

x = \frac{4 e ^{2}}{3}

Verify Solutions:

x = \frac{4 e ^{2}}{3}

True

The solution is

x = \frac{4 e ^{2}}{3}

k, lo g_{k} (a) = b - 2

lo g_{x} (3) = 31

lo g_{x} (8) = 1 \cdot 5

y, ln (x^{3} y^{3}) = c

x + ln (x) = - 4

What is the answer to ln(3x)-ln(4)=2 ?
The answer to ln(3x)-ln(4)=2 is x=(4e^2)/3
Solve for x: ln(3x)-ln(4)=2
The solution is x=(4e^2)/3