What is the answer to log_{3}(x^2+4x)=4 ?

The answer to log_{3}(x^2+4x)=4 is x=-2+sqrt(85),x=-2-sqrt(85)

Solve for x: log_{3}(x^2+4x)=4

The solution is x=-2+sqrt(85),x=-2-sqrt(85)

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lo g_{3} (x^{2} + 4 x) = 4

x = - 2 + 85, x = - 2 - 85

Decimal Notation

x = 7.21954 \dots, x = - 11.21954 \dots

Solution steps

lo g_{3} (x^{2} + 4 x) = 4

Apply log rules

x^{2} + 4 x = 81

Solve

x^{2} + 4 x = 81 : x = - 2 + 85, x = - 2 - 85

x = - 2 + 85, x = - 2 - 85

lo g_{3} (81) = 4 lo g_{3} (x + 1)

ln (1.8) - ln (x) = 0.2742

lo g_{10} (x - 1) = 3.4

3 lo g_{5} (25 x) = 12

lo g_{10} (x - 1) = 3, x

What is the answer to log_{3}(x^2+4x)=4 ?
The answer to log_{3}(x^2+4x)=4 is x=-2+sqrt(85),x=-2-sqrt(85)
Solve for x: log_{3}(x^2+4x)=4
The solution is x=-2+sqrt(85),x=-2-sqrt(85)