What is the answer to log_{10}(x^4)=(-2)/5 ?

The answer to log_{10}(x^4)=(-2)/5 is x= 1/(sqrt(\sqrt[5]{10))},x=-1/(sqrt(\sqrt[5]{10))}

Solve for x: log_{10}(x^4)=(-2)/5

The solution is x= 1/(sqrt(\sqrt[5]{10))},x=-1/(sqrt(\sqrt[5]{10))}

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lo g_{10} (x^{4}) = \frac{- 2}{5}

Decimal Notation

x = 0.79432 \dots, x = - 0.79432 \dots

Solution steps

lo g_{10} (x^{4}) = \frac{- 2}{5}

Apply exponent rule:

a^{2 \cdot n} = (a^{2})^{n}

x^{4} = (x^{2})^{2}

lo g_{10} ((x^{2})^{2}) = \frac{- 2}{5}

Apply log rules

Solve

Verify Solutions:

True

The solutions are

x, z = ln (x + y - 5)

x + 1 = 4^{l o g_{2} (x - 1)}

ln (x) = a + b

10 = 8 + lo g_{10} (x)

lo g_{2} (x) - lo g_{4} (x^{2}) = 4

What is the answer to log_{10}(x^4)=(-2)/5 ?
The answer to log_{10}(x^4)=(-2)/5 is x= 1/(sqrt(\sqrt[5]{10))},x=-1/(sqrt(\sqrt[5]{10))}
Solve for x: log_{10}(x^4)=(-2)/5
The solution is x= 1/(sqrt(\sqrt[5]{10))},x=-1/(sqrt(\sqrt[5]{10))}