What is the answer to ln(16x)-ln(4)=2 ?

The answer to ln(16x)-ln(4)=2 is x=(e^2)/4

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ln(16x)-ln(4)=2

ln (16 x) - ln (4) = 2

x = \frac{e ^{2}}{4}

Decimal Notation

x = 1.84726 \dots

Solution steps

ln (16 x) - ln (4) = 2

Move

ln (4)

to the right side

ln (16 x) = 2 + ln (4)

Apply log rules

16 x = 4 e^{2}

Solve

16 x = 4 e^{2} : x = \frac{e ^{2}}{4}

x = \frac{e ^{2}}{4}

Verify Solutions:

x = \frac{e ^{2}}{4}

True

The solution is

x = \frac{e ^{2}}{4}

lo g_{10} (y) = 2 t + 4, y

(ln (x))^{2} - ln (x^{3}) - 10 = 0

3 lo g_{3} (x) + lo g_{3} (x^{2}) = 5

x, z = ln (x^{2} y)

lo g_{2} ((4 x + 6)^{2}) = 4

What is the answer to ln(16x)-ln(4)=2 ?
The answer to ln(16x)-ln(4)=2 is x=(e^2)/4
Solve for x: ln(16x)-ln(4)=2
The solution is x=(e^2)/4