What are the solutions to the equation b^2=(47)^2+(56)^2 ?

The solutions to the equation b^2=(47)^2+(56)^2 are b=sqrt(5345),b=-sqrt(5345)

Find the zeros of b^2=(47)^2+(56)^2

The zeros of b^2=(47)^2+(56)^2 are b=sqrt(5345),b=-sqrt(5345)

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b^{2} = (47)^{2} + (56)^{2}

b = 5345, b = - 5345

Decimal Notation

b = 73.10950 \dots, b = - 73.10950 \dots

Solution steps

b^{2} = (47)^{2} + (56)^{2}

Simplify

4 7^{2} + 5 6^{2} : 5345

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 5345, b = - 5345

28 x^{2} + 16 x + 2 = 0

r^{3} - 1

9 m^{2} - 49

b^{2} + 2 b - 24

(\frac{4 x ^{5}}{y ^{2} z})^{2}

What are the solutions to the equation b^2=(47)^2+(56)^2 ?
The solutions to the equation b^2=(47)^2+(56)^2 are b=sqrt(5345),b=-sqrt(5345)
Find the zeros of b^2=(47)^2+(56)^2
The zeros of b^2=(47)^2+(56)^2 are b=sqrt(5345),b=-sqrt(5345)