What is the answer to log_{3}(2x-7)=log_{3}(13-3x) ?

The answer to log_{3}(2x-7)=log_{3}(13-3x) is x=4

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log_{3}(2x-7)=log_{3}(13-3x)

lo g_{3} (2 x - 7) = lo g_{3} (13 - 3 x)

x = 4

Solution steps

lo g_{3} (2 x - 7) = lo g_{3} (13 - 3 x)

Apply log rules

2 x - 7 = 13 - 3 x

Solve

2 x - 7 = 13 - 3 x : x = 4

x = 4

Verify Solutions:

x = 4

True

The solution is

x = 4

ln (x - 2) + 1 = 0

lo g_{3} ((x + 51)^{5}) = 20

- lo g_{10} (x) = 6.2

x^{l o g_{10} (x)} = 100 \cdot x

1 n^{2} = 2 n lo g_{10} (n)

What is the answer to log_{3}(2x-7)=log_{3}(13-3x) ?
The answer to log_{3}(2x-7)=log_{3}(13-3x) is x=4
Solve for x: log_{3}(2x-7)=log_{3}(13-3x)
The solution is x=4