What is the answer to solvefor y,-ln(y+6)=x^2 ?

The answer to solvefor y,-ln(y+6)=x^2 is y=e^{-x^2}-6

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solvefor y,-ln(y+6)=x^2

solve for

y, - ln (y + 6) = x^{2}

y = e^{- x^{2}} - 6

Solution steps

- ln (y + 6) = x^{2}

Divide both sides by

- 1

ln (y + 6) = - x^{2}

Apply log rules

y + 6 = e^{- x^{2}}

Solve

y + 6 = e^{- x^{2}} : y = e^{- x^{2}} - 6

y = e^{- x^{2}} - 6

Verify Solutions:

y = e^{- x^{2}} - 6

True

The solution is

y = e^{- x^{2}} - 6

2 = lo g_{10} (2^{8} \frac{1}{x})

6 (ln (2 x) + 1) = 0

lo g_{x} (8) = \frac{3}{2}

ln (x) = - a

3 lo g_{10} (2 y) = - 6

What is the answer to solvefor y,-ln(y+6)=x^2 ?
The answer to solvefor y,-ln(y+6)=x^2 is y=e^{-x^2}-6