What is the answer to log_{10}(3x)+log_{10}(x+2)=7 ?

The answer to log_{10}(3x)+log_{10}(x+2)=7 is x=(-6+sqrt(120000036))/6

Solve for x: log_{10}(3x)+log_{10}(x+2)=7

The solution is x=(-6+sqrt(120000036))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{10} (3 x) + lo g_{10} (x + 2) = 7

x = \frac{- 6 + 120000036}{6}

Solution steps

lo g_{10} (3 x) + lo g_{10} (x + 2) = 7

Apply log rules

3 x (x + 2) = 10000000

Solve

3 x (x + 2) = 10000000 : x = \frac{- 6 + 120000036}{6}, x = \frac{- 6 - 120000036}{6}

x = \frac{- 6 + 120000036}{6}, x = \frac{- 6 - 120000036}{6}

Verify Solutions:

x = \frac{- 6 + 120000036}{6}

True

, x = \frac{- 6 - 120000036}{6}

False

The solution is

x = \frac{- 6 + 120000036}{6}

lo g_{x} (2) + lo g_{2} (x) = 2

lo g_{x} (2) + lo g_{2} (x) = 0

x, ln (3 x - 13) = 3

ln (2 x) - ln (x^{2} - 3) = 0

lo g_{10} (x^{3} + 200) = 2

What is the answer to log_{10}(3x)+log_{10}(x+2)=7 ?
The answer to log_{10}(3x)+log_{10}(x+2)=7 is x=(-6+sqrt(120000036))/6
Solve for x: log_{10}(3x)+log_{10}(x+2)=7
The solution is x=(-6+sqrt(120000036))/6