What is the answer to log_{10}(7x-2)=0 ?

The answer to log_{10}(7x-2)=0 is x= 3/7

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log_{10}(7x-2)=0

lo g_{10} (7 x - 2) = 0

x = \frac{3}{7}

Solution steps

lo g_{10} (7 x - 2) = 0

Apply log rules

7 x - 2 = 1

Solve

7 x - 2 = 1 : x = \frac{3}{7}

x = \frac{3}{7}

x, - 2 = lo g_{2} (x)

ln (2 - p) = 4

lo g_{10} (x^{2} - 44) = 2

P, lo g_{P} (- 1) = n

0 = 4 (ln (4 x) + 1)

What is the answer to log_{10}(7x-2)=0 ?
The answer to log_{10}(7x-2)=0 is x= 3/7
Solve for x: log_{10}(7x-2)=0
The solution is x= 3/7