What is the answer to 0=4(ln(4x)+1) ?

The answer to 0=4(ln(4x)+1) is x= 1/(4e)

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0=4(ln(4x)+1)

0 = 4 (ln (4 x) + 1)

x = \frac{1}{4 e}

Decimal Notation

x = 0.09196 \dots

Solution steps

0 = 4 (ln (4 x) + 1)

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

ln (4 x) + 1 = 0

Solve

ln (4 x) + 1 = 0 : x = \frac{1}{4 e}

Verify Solutions:

x = \frac{1}{4 e}

True

The solution is

x = \frac{1}{4 e}

lo g_{10} (x + 2) = 2.19

ln (4 x + 5) = 10

60 = 9.95593 ln (x) + 68.691

a = lo g_{10} (x - 4)

ln (x) = 30