What is the answer to ln(x)=ln(5)+ln(x-7) ?

The answer to ln(x)=ln(5)+ln(x-7) is x= 35/4

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ln(x)=ln(5)+ln(x-7)

ln (x) = ln (5) + ln (x - 7)

x = \frac{35}{4}

Solution steps

ln (x) = ln (5) + ln (x - 7)

Apply log rules

x = 5 (x - 7)

Solve

x = 5 (x - 7) : x = \frac{35}{4}

x = \frac{35}{4}

Verify Solutions:

x = \frac{35}{4}

True

The solution is

x = \frac{35}{4}

lo g_{2 x} (2 x^{2} + 6 x - 4) = 2

10 lo g_{10} (x^{2}) = - 20

2 5^{l o g_{5} (3 x^{2})} = 9 x^{2}

lo g_{10} (x) = - 13.9

lo g_{2} (x + 19) + lo g_{2} (x + 4) = 4

What is the answer to ln(x)=ln(5)+ln(x-7) ?
The answer to ln(x)=ln(5)+ln(x-7) is x= 35/4
Solve for x: ln(x)=ln(5)+ln(x-7)
The solution is x= 35/4