What is the answer to 25^{log_{5}(3x^2)}=9x^2 ?

The answer to 25^{log_{5}(3x^2)}=9x^2 is x=1,x=-1

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25^{log_{5}(3x^2)}=9x^2

2 5^{l o g_{5} (3 x^{2})} = 9 x^{2}

x = 1, x = - 1

Solution steps

2 5^{l o g_{5} (3 x^{2})} = 9 x^{2}

Apply log rules

x^{2} = 1

Solve

x^{2} = 1 : x = 1, x = - 1

x = 1, x = - 1

Verify Solutions:

x = 1

True

, x = - 1

True

The solutions are

x = 1, x = - 1

lo g_{10} (x) = - 13.9

lo g_{2} (x + 19) + lo g_{2} (x + 4) = 4

x^{1 + l n (x)} = e^{4} \cdot x

lo g_{x} (2 + 2) = 3

- 3 - ln (- 3 + x) = 0

What is the answer to 25^{log_{5}(3x^2)}=9x^2 ?
The answer to 25^{log_{5}(3x^2)}=9x^2 is x=1,x=-1
Solve for x: 25^{log_{5}(3x^2)}=9x^2
The solution is x=1,x=-1